(X^2-10/x+2)+x-4=x-3

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Solution for (X^2-10/x+2)+x-4=x-3 equation: 



(X^2-10/X+2)+X-4=X-3

We move all terms to the left:

(X^2-10/X+2)+X-4-(X-3)=0



Domain of the equation: X+2)!=0

X∈R



We add all the numbers together, and all the variables

X+(X^2-10/X+2)-(X-3)-4=0

We get rid of parentheses

X^2+X-10/X-X+2+3-4=0

We multiply all the terms by the denominator


X^2*X+X*X-X*X+2*X+3*X-4*X-10=0

We add all the numbers together, and all the variables

X^2*X+X+X*X-X*X-10=0

Wy multiply elements

X^3+X^2-1X^2+X-10=0

We do not support eXpression: X^3

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